从类似如下的文本文件中读取出所有的姓名，并打印出重复的姓名和重复的次数，并按重复次数排序：

1,张三,28
2,李四,35
3,张三,28
4,王五,35
5,张三,28
6,李四,35
7,赵六,28
8,田七,35

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import java.util.Set;

public class AnswerB06 {

    public static void main(String[] args) throws IOException {
        Map<String, Integer> nameMap = new HashMap<String, Integer>();

        BufferedReader reader = new BufferedReader(new InputStreamReader(AnswerB06.class.getResourceAsStream("/person.txt")));
        String line = null;
        while ((line = reader.readLine()) != null) {
            String[] segments = line.split(",", -1);
            String name = segments[1];
            Integer count = nameMap.get(name);
            if (count == null) {
                count = 0;
            }
            count++;
            nameMap.put(name, count);
        }
        reader.close();

        List<PersonCount> personCounts = new ArrayList<PersonCount>();
        Set<String> names = nameMap.keySet();
        for (String name : names) {
            PersonCount personCount = new PersonCount();
            personCount.name = name;
            personCount.count = nameMap.get(name);
            personCounts.add(personCount);
        }
        
        Collections.sort(personCounts);
        
        for (PersonCount personCount : personCounts) {
            System.out.println(personCount.name + "=" + personCount.count);
        }
    }

    static class PersonCount implements Comparable<PersonCount> {
        public String name;
        public int count;

        @Override
        public int compareTo(PersonCount o) {
            return count - o.count;
        }
    }
}